Write the balanced nuclear reaction for the decay of iodine-137 to xenon-137.

Explanation:

First off, it is important to know the type of decay that Iodine undergo to give Xenon.

This is achieved by comparing the mass number and atomic number of the products and reactants.

Iodine

Mass Number = 137

Atomic Number = 53

Xenon

Mass Number = 137

Atomic Number = 54

Upon comparison, we can tell that the only change is the increase in the atomic numbers.

Due to this, we now know it is a beta decay. In beta decay, one of the neutrons in the nucleus suddenly changes into a proton, causing an increase in the atomic number of an element.

In a balanced nuclear equation, the sum of the mass numbers on the reactant side must equal the sum of the mass numbers on the product side. The same must be true for the atomic numbers.

Reactant side;

Mass number = 137

Atomic Number = 53

Product side;

Mass number = 137 +0 = 137

Atomic Number = 54 + (-1) = 53

The equation is given in the attachment.

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation: