Consider an ideal gas enclosed in a 1.00 l container at an internal pressure of 18.0 atm. calculate the work, w , if the gas expands against a constant external pressure of 1.00 atm to a final volume of 18.0 l.

-32821.2 J (negative sign implies that work is done by the system)

Explanation:

The expression for the calculation of work done is shown below as:

Where, P is the pressure

is the change in volume

From the question,  

= 18.0 - 1.00 L = 18.0 L

P = 18.0 atm

Also, 1 atmL = 101.3 J

So,  

(negative sign implies that work is done by the system)