A22.5 g sample of a metal is heated to 65.00 °c and added to 25.00 g of water (c = 4.184 j/g °c) in a calorimeter. the water temperature rises from 25.55 °c to 35.25 °c. what is the specific heat capacity of the metal?

The specific heat capacity of the metal is 1.143 J/g°C

Explanation:

A typical excersise of calorimetry:

Q = m . C . ΔT

ΔT = Final T° - Initial T°

m = mass

In this case, the heat released by the metal is gained by the water to rise its temperature.

Qmetal = Qwater

(We consider that metal was at the same T° of water)

22.5 g  . C . (65°C - 25.55°C) = 25 g .  4.184 J/g°C . (35.25°C - 25.55°C)

22.5 g  . C . 39.45°C = 25g . 4.184 J/g°C . 9.7°C

887.625 g.°C . C = 1014.62J

C = 1014.62J / 887.625 g.°C

C = 1.143 J/g°C

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

16

explanation:

the marks go by 4s