Ethanol (ch3ch2oh) has been suggested as an alternative fuel source. ethanol’s enthalpy of combustion is hcomb = –1368 kj/mol. what volume of ethanol (d = 0.789 g/ml) is required to produce the same amount of energy as 1 gallon of gasoline, which can be modeled as isooctane (c8h18) with an energy density of 32.9 kj/ml? (1 gal = 3.785 l; d = 0.703 g/ml)

a. 1.41 gal
b. 0.85 gal
c. 1.00 gal
d. 1.15 gal
d. 0.90 ga

a) V = 1.41 gal

Explanation:

Ethanol:

∴ Hcomb = - 1368 KJ/mol( - ) exothermic reaction

∴ δ = 0.789 g/mL

∴ Mw Ethanol = 46.07 g/mol

⇒ Eδ = (1368 KJ/mol)(mol/46.07 g)(0.789 g/mL) = 23.4285 KJ/mL

isooctane:

∴ Eδ = 32.9 KJ/mL

∴ δ = 0.703 g/mL

⇒ E = (32.9 KJ/mL)(3785 mL) = 124526.5 KJ

Volume of Ethanol:

⇒ (Eδ)(V) = 124526.5 KJ

⇒ V = (124526.5 KJ)/(23.4285 KJ/mL) = 5315.167 mL

⇒ V = (5315.167 mL)( gal/3785 mL) = 1.404 gal ≅ 1.41 gal

answer: lol

explanation:

lol

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.