What is the rate law for the reaction below: a + b + c dif the following data were collected? exp [a]0 [b]0 [c]0 initial rate1 0.4 1.2 0.7 2.32x10-32 1.3 1.2 0.9 7.54x10-33 0.4 4.1 0.8 9.25x10-24 1.3 1.2 0.2 7.54x10-3this is the explanation i was given but i still don't understan it. can you show the steps for solving the exponents of the rate laws "with algebra"? : the general form of the rate law has to be: rate = k [a]x [b]y [c]zusing the experiments given to set up several equations, we get: 2.32x10-3 = k(0.4)x(1.2)y(0.7)z7.54x10-3 = k(1.3)x(1.2)y(0.9)z9.25x10-2 = k(0.4)x(4.1)y(0.8)z7.54x10-3 = k(1.3)x(1.2)y(0.2)zwith algebra, we find x=1, y=3, and z=0. plugging these values in, we get the rate law as: rate = k [a] [b]3 [c]0 = k [a] [b]3we can now plug in any experiment into the rate law above to solve for k. plugging in experiment 1: 2.32x10-3 = k(0.4)(1.2)3k = 3.36x10-3the complete rate law: rate = 3.36x10-3 [a] [b]3

rate = k  [A] [B] ³

Explanation:

Set up a table with the data given in the question to study the dependence of the reaction rate on the concentrations of reactants.

[A]             [B]             [C]             Rate           Experiment #

0.4            1.2             0.7          2.32 x 10⁻³        (1)

1.3            1.2             0.9          7.54 x 10⁻³        (2)

0.4             4.1            0.8          9.25 x 10⁻²        (3)

1.3              1.2             0.2         7.54 x 10⁻³        (4)

The rate law will have the form : rate =  k [A] ^x   [B]  ^y    [C]   ^z

Comparing experiments (2) and (4) we have to conclude that  the rate  is zero order with respect to  [C]  since keeping [A]  and [B]  the same and varying [C] did not change the rate (i.e ,no dependence on  [C]) .

Now we know the rate law has the form rate =  k [A] ^x  [B]  ^y

Comparing (1) and (4) we keep [B] constant and increase [A] by a factor of  1.3/.4 = 3.25 and the rate increased by a factor of 0.00754 / 0.00232 =3.25, so we can conclude that the rate law is first order with respect to  [A]

Finally, comparing (1) and (3) while keeping  [A]  constant  increasing [B] by a factor of 4.1/1.2 = 3.416, the rate increased by a factor of 0.0925/0.00232 = 40, it is not entirely clear the dependence with respect to  [B] .

In this case we can always set up the following equation which is obtained by dividing  equation (3) by (1)

(4.1 / 1.2)^x = 0.0925/0.00232

taking natural log to both sides of the equation

x ln 3.4167 = ln 40

x = 3.69/1.23 = 3

So the dependence with respect to   [C] is three.

The rate law is :

rate = k  [A] [B] ³

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.