Are the strengths of the interactions between the particles in the solute and between the particles in the solvent before the solute and solvent are combined greater than, less than, or equal to the strengths of the interactions between solute particles and solvent particles after dissolution?

For the dissolution of the solute particles in the solvent particles, the force of attraction between the particles of solute and between the particle of solvent must be less than the interaction between the solute particles and solvent particles after dissolution.

In a solution, the forces act are present between the solute molecules, solvent molecules, and solute-solvent molecules. For the dissociation to occur the bond between the solute and solvent particles has to be broken. The resultant will result in the dissolution of the solute in the solvent mixture. The strong solute-solute and solvent-solvent bond will result in difficulty in the formation of the solute-solvent bond, and the dissolution will not take place.

Thus for the dissolution of the solute particles in the solvent particles, the force of attraction between the particles of solute and solvent must be less than the interaction between the solute particles and solvent particles after dissolution.

For more information about dissolution, refer to the link:

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Solute-solvent interaction increases after dissolution. Solute-solvent interaction is greater after dissolution.

Explanation:

When a substance is dissolved, the interaction between solute particles gives way to new stronger interaction with the solvent which makes the solid disappear and form a continuous homogeneous phase with the solvent. When this occurs, the solute has dissolved in the solvent.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j