Chemistry, 25.12.2019 03:31 mihirkantighosh

Ask your teacher you are given two clear, colorless aqueous solutions. you are told that one solution contains an ionic compound, and one contains a covalent compound. how could you determine which is an ionic solution and which is a covalent solution?

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Answer from: hi105

Explanation:

Ionic compound are compounds formed by one atom losing an electron while the other gains electron as such the solution always contain charge ions compared to covalent solution which is predominantly formed by two atoms sharing electron. The two solution should be connected to a circuit with a bulb in turns with the same circuit, the solution that turns the bulb on is the ionic solution. This is because their charged ions conducts electricity when voltage is passed through it while the covalent solution does not conduct electricity.

Answer from: Quest

b) mutualism

hope this : )

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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