Answers: 2
is -238 kJ/mol
![\Delta H=\sum [n\times B.E(reactant)]-\sum [n\times B.E(product)]](/tpl/images/0434/0215/42942.png)
![\Delta H=[(n_{A_2}\times B.E_{A_2})+(n_{B_2}\times B.E_{B_2}) ]-[(n_{AB}\times B.E_{AB})]](/tpl/images/0434/0215/c021c.png)
![\Delta H=[(1\times x)+(1\times B.E_{B_2}) ]-[(2\times 2x)]](/tpl/images/0434/0215/7aa1f.png)
![-321=[(1\times x)+(1\times 393)]-[(2\times 2x)]](/tpl/images/0434/0215/06819.png)
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Consider the following reaction: a2 + b2 → 2ab δh = –321 kj bond energy (a2) = 1/2ab bond energy (b...
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