Chemistry, 26.12.2019 22:31 DavidsonSaid
The acid dissociation constant ka of boric acid (h3bo3) is 5.8 times 10^-10. calculate the ph of a 4.4 m solution of boric acid. round your answer to 1 decimal place.
Answers: 3
= ?
![[H^+]=c\times \alpha](/tpl/images/0434/0871/4fc41.png)
![[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M](/tpl/images/0434/0871/865ab.png)
![pH=-log[H^+]](/tpl/images/0434/0871/15713.png)
![pH=-log[4.8\times 10^{-5}]=4.3](/tpl/images/0434/0871/ee066.png)
solution is 4.3
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The acid dissociation constant ka of boric acid (h3bo3) is 5.8 times 10^-10. calculate the ph of a 4...
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