What is the specific heat capacity 82.4g of a metal that is absorbed 846 joules of heat as the temperature increases from 25c to 67c

Specific heat capacity = 0.24 j/g.°C

Explanation:

Given data:

Mass of metal = 82.4 g

Heat absorbed = 846 j

Change in temperature = 67°C - 25°C

Specific heat capacity = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 67°C - 25°C

ΔT = 42°C

Q = m.c. ΔT

846 j = 82.4 g . c. 42°C

c = 846 j / 3460.8 g.°C

c = 0.24 j/g.°C

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey

altitude, density, pressure

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