How many grams of fe is needed to react with 35.0 g of sulfuric acid in the following reaction? 3h2so4 + 2fe -> fe2(so4)3 + 3h2

13.3 g

Explanation:

Let's consider the following reaction.

3 H₂SO₄ + 2 Fe → Fe₂(SO₄)₃ + 3 H₂

The molar mass of H₂SO₄ is 98.1 g/mol. The moles of H₂SO₄ in 35.0 g are:

35.0 g × (1 mol / 98.1 g) = 0.357 mol

The molar ratio of H₂SO₄ to Fe is 3:2. The moles of Fe are:

0.357 mol H₂SO₄ × (2 mol Fe/ 3 mol H₂SO₄) = 0.238 mol

The molar mass of Fe is 55.8 g/mol. The mass of Fe is:

0.238 mol × (55.8 g/mol) = 13.3 g

the answer is c

tell me if wrong