)nitrogen gas is heated so that it undergoes the process pictured below. how much heat is required to do this? under these conditions nitrogen behaves like an ideal gas. note that 1 atm = 101 kpa.

(approximately 400 J)

It seems like the question is not complete, but I will asume the volume is changing from 1000 to 3000  cm3.  under constant presure(2 atm).

Explanation:

So, this is called "Isobaric process" because the presure is not changing while the volume does.

So, you just have to use the ecuation at the image.

P(V2-V1)

=2 atm (3000-1000)cm3

=4 atm . L = 405,26 J =   (approximately 400 J)

the answer is b. dilution