Ammonia undergoes combustion to yield nitric oxide and water by the following reaction equation: 4 nh3 (g) + 5 o2 (g) → 4 no (g) + 6 h2o (g) δh = - 1170 kjif 26.5 g of nh3 is reacted with excess o2, what will be the amount of heat given off?

-455 kJ

Explanation:

Let's consider the following thermochemical equation.

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g) ΔH = -1170 kJ

1170 kJ of heat are released per 4 moles of NH₃. Considering that the molar mass of NH₃ is 17.03 g/mol, the amount of heat given of by 26.5 g of NH₃ is: