Atypical lead acid storage battery like the one found in your car is 12 v and is rated at 70 amp-hr (70 amp of current drawn for 1 hour). volts x amps gives you watts.
so the energy stored in the fully charged battery is 840 watt-hours (wh). remember that a kwh = 3600 kj.

if a snicker's bar contains 250 cal and 1 cal = 4.184 kj, how many snicker's bars worth of energy is stored in your battery?

a. fewer than 5

b. 5-20

c. 20-50

d. 50-100

e. more than 100

Almost 3 snicker's bar will contain the worth of energy stored in the battery which makes option A correct (Fewer than 5)

Explanation:

Step 1

The energy stored in a charged battery is 840 Watt- hours

Recall from the question that 1 KWh = 3600 KJ

So how many Kilo-joules will be in 840 Watt- hours?

I will convert 840 Watt- hours to KWh = 840 / 1000

                                                              = 0.840 KWh

Since I KWh gives 3600 KJ

then, 0.840 KWh will give x

                                          x = 3024 KJ

3024 KJ of energy is stored in the battery

Step 2

A snicker bar contains 250 cal and 1 cal = 4.184 KJ

Convert 250 cal to KJ?

250 cal = 1046 KJ

Each snicker bar contains 1046 KJ

To calculate how many snicker's bar worth energy stored in the battery will be (y) ?

y = 3024 / 1046

y = 2.9 snicker's bar approximately 3

The correct option is Fewer than 5

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

answer: gold foil experiment - he shot alpha particles at a gold foil

explanation: