Which of the following substances would be a poor choice for making conductive solutions?

a)
c6h12o6, ch3oh, ch3ch2oh

b)
hcl, kbr, hno3

c)
naoh, koh, lioh

a)  C₆H₁₂O₆, CH₃OH, CH₃CH₂OH

Explanation:

For a solution to be conductive, it requires to have electrolytes, that is, species that dissociate into ions and carry electrical charges.

Which of the following substances would be a poor choice for making conductive solutions?

a)  C₆H₁₂O₆, CH₃OH, CH₃CH₂OH

These species are formed exclusively by covalent bonds and they are non-electrolytes, that is, they practically do not form ions in water. Therefore, a solution containing these species would be poorly conductive.

b)  HCl, KBr, HNO₃

The species are formed by ionic and covalent bonds and are electrolytes. Thus, their solutions are conductive.

c)  NaOH, KOH, LiOH

The species are formed by ionic and covalent bonds and are electrolytes. Thus, their solutions are conductive.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%