Write the values for the four quantum numbers for a 4f6 electron.2.write the values for the four quantum numbers for a 3s1 electron.3.write the values for the four quantum numbers for the last electron to fill 28ni.4.write the values for the four quantum numbers for the outermost electron in 22ti.

The electron configuration shows the arrangement of electrons in atoms.

The electron configuration gives a description of the location of the electron in an atom.

Note that;

n = Principal quantum number

l = orbital quantum number

m = magnetic quantum number

s = spin quantum number

n = 4, l = 3, m = 3, -2, -1, 0, 1, 2, 3, s= ±1/2

n = 3, l = 0, m = 0, s = ±1/2

n = 4, l = 0, m = 0, s = ±1/2

n = 4, l = 0, m = 0, s = ±1/2

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Explanation:

Data given:

Values for four Quantum number for

1.  4f⁶ = ?

2.  3s¹ = ?

3. last electron to fill ²⁸Ni = ?

4. for the outermost electron in ²²Ti = ?

Solution:

Atom is made up of electron, proton and neutron. electron revolve in the orbital around the nucleus and can be identified by its quantum number.

the quantum number of an electron give information about the energy and position of the electron in atom

General formulas to calculate quantum number

There are 4 quantum numbers that have its own specification

1.  Principal quantum number:

it give us information about main shells

it is represented by "n" and can be 1, 2, 3, 4 ,5 so on

So,

Principal quantum number = n

2. Azimuthal quantum number

it give us information about angular momentum and shape of orbitals

it is denoted by "l" and can be 0, 1, 2, 3, 4 ,5 so on

So,

Azimuthal quantum number = l and calculated by n-1 formula

3.  Magnetic quantum number

it give us information about orbitals available in a sub-shell and orientation of orbitals in space

it is denoted by "m" and can be (-l, 0, +l) i.e  -1, 0, +1

Magnetic quantum number = m and calculated by -l, 0, +1 formula

4. Spin quantum number

it give us information about spin of electron around its axis in orbital

it is denoted by "s"

it can be +1/2 or -1/2

Spin quantum number = +1/2 or -1/2

now calculate for each one by one

1.  4f⁶

        put values in formula

                    n-1 = 4-1 = 3

Azimuthal quantum number = l = 3

calculated by -l, 0, +l formula

So, l = 3 so "m" will be

-3, -2, -1, 0, +1, +2, +3

2.  3s¹ =

        put values in formula

                    n-1 = 3-1 = 2

Azimuthal quantum number = l = 3

calculated by -l, 0, +l formula

So, l = 2 so m will be

-2, -1, 0, +1, +2,

3. last electron to fill ²⁸Ni = ?

first we will look for the electronic configuration of ²⁸Ni

configuration of ²⁸Ni = [Ar], 3d⁸, 4s²

So the last electrons to fill is 4s²

        put values in formula

                    n-1 = 4-1 = 3

Azimuthal quantum number = l = 3

calculated by -l, 0, +l formula

So, l = 2 so m will be

+3, -2, -1, 0, +1, +2, +3

4. for the outermost electron in ²²Ti = ?

first we will look for the electronic configuration of ²²Ti

configuration of ²²Ti = [Ar], 3d²

So the last electrons to fill is 3d²

        put values in formula

                    n-1 = 3-1 = 2

Azimuthal quantum number = l = 2

calculated by -l, 0, +l formula

So, l = 2 so m will be

-2, -1, 0, +1, +2

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml