What mass of compound 1 (mw = 800 g/mol) is contained in the solution used to prepare liposomes that elute at 20 ml by size-exclusion chromatography?

Mass of compound 1 is 0.7144g

Explanation:

1 mole of liposomes =22.4L

20mL (0.02L) of liposomes = 0.02/22.4 = 0.000893mole

Number of moles = Mass/Molecular Weight (MW)

Mass = Number of moles × MW = 0.000893 × 800 = 0.7144g

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

the formula mass of a molecule or a compound is the sum of the atomic weights of the atoms in its empirical formula

(that's what i know about formula mass)