Write electron (subshell) configurations for the following atoms: a.15p b. 19k c. 28ni d. 35br e. 58ce

15P) 3s² 3p³

19K) 4s¹

28Ni) 3d⁸ 4s²

35Br) 3d¹⁰ 4s² 4p⁵

58Ce) 4f¹ 5d¹ 6s²

Explanation:

1) 15P

Phosphorus has 15 electrons

The order of filling of the energy levels is 1s, 2s, 2p, 3s, 3p, 4s, . . .

The 15 electrons of the phosphorus atom will fill up to the 3p orbital, which will contain three electrons

The electron configuration for 15P is: 1s2 2s2 2p6 3s2 3p3

3s² 3p³

2) 19K

Potassium has 19 electrons

The electron configuration for 19K is: 1s2 2s2 2p6 3s2 3p6 4s1

4s¹

3) 28Ni

Nickel has 28 electrons

The electron configuration for 28Ni is: 1 s 2  2 s 2  2 p 6  3 s 2  3 p 6  4 s 2  3 d 8

3d⁸ 4s²

4) 35Br

Bromine has 35 electrons

The electron configuration for 35Br is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5

3d¹⁰ 4s² 4p⁵

5) 58Ce

Cerium has 58 electrons

The electron configuration for 58Ce is: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f1 5d1

4f¹ 5d¹ 6s²

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml