Which of the following correctly describes the orbital hybridization of xef4 and nh3, respectively? a. sp3d2, sp3b. sp3, sp3c. sp3, sp2d. sp3d2, sp2

A

Explanation:

Hybridization is simply a phenomena which involves the mixing of orbitals to form new ones. It is simply a way of forming a whole new set of orbitals from old ones.

In XeF4, the type of hybridization that we have is the sp3d2 hybridization. This simply means we have one s orbital, mixing with 3 p orbitals and 2 d orbitals. These orbitals mix together to form the new hybrid orbital. It must be noted that the hybridization takes place in the central atom xenon Xe. The valence shell of xenon contains 2 electrons in the 5s orbital and 6 electrons in the 5p orbitals. In the state of excitement, 2 of the electrons in the outermost 5p orbitals get excited and promoted to the 5d orbitals. This causes a total of four unpaired electrons in which the four chlorine atom can attach with.

In ammonia, there are three hydrogen atoms which seek to join forces with a single nitrogen atom. It must be known that there are 8 electrons around the central atom nitrogen. There are a set of lone pair which are non bonding while the other three are in connection with the 3 hydrogen atoms. Instead of the molecule having 1s and 3p orbitals, they show hybridization to give sp3 hybrid orbital

it should be all of them because it asks if you included all of those in your answer

explanation:

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.