How many days have passed if 19.2 mg of calcium-47 decayed to 1.2 mg of calcium-47?

This is a problem involving half-lives. We can solve this problem by using the equation as shown: A=Aoe^-(ln2/t)T where A is the final amount (1.2milligram), Ao is the initial amount (19.2mg), t is the half-life (4.5 days) and lastly T time elapsed (required). Plug in the values in the equation and you should get  18 days. Eighteen days have passed.

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