What is the molality of a solution prepared by dissolving 86.9 g of diethyl ether, c4h10o, in 425 g of benzene, c6h6?

Molality is 2.76 m/kg

Explanation:

First of all, determinate the moles of solute by dividing mass / molar mass

Molar mass diethyl ether = 74.12 g/m

86.9 g / 74.12 g/m = 1.17 moles

This moles of solute, are in 425 grams of benzene (solvent)

Molality means, the moles of solute which occupy 1kg of solvent.

425 g = 0.425 kg

1.17 m / 0.425 kg = 2.76 m

The molality of this solution is 2.75 molal

Explanation:

Step 1: Data given

Mass of diethyl ether = 86.9 grams

Mass of benzene = 425 grams = 0.425 kg

Step 2: Calculate moles of solute

Molality = moles of solute/kg of solvent

Molar mass of C4H10O =

4* molar mass carbon + 10* molar mass hydrogen + molar mass of oxygen

molar mass C4H10O = 74.12 g/mol

Moles solute( C4H10O) = 86.9 grams / 74.12 g/mol

Moles C4H10O = 1.17 moles

Step 3: Calculate molality

Molality = 1.17 moles of C4H10O / 0.425 kg of C6H6

Molality = 2.75 mol/kg = 2.75 molal

The molality of this solution is 2.75 molal

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i  

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