How many moles of nacl are present in 600 ml of a 1.55 m nacl solutions

The answer is 2.583 moles

Explanation:

molarity is defined as the number of moles divided by the volume of the solution, as follows:

M = nmoles/Volume

Clearing the nmoles:

600 mL = 0.6 L

nmoles = MxVolume = 1.55 mol/L x 0.6 L = 2.583 moles

the answer would be a

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.