What is the mass in grams of 2.30 x10^23 molecules of fluorine

14.512g

Explanation:

Using the expression

mole = Number of molecules/6.022 x 10^23

mole of Fluorine = 2.30 x10^23/6.022 x 10^23

                             =  0.3819 mol

However,

mole = mass / molarmass

Mass of Fluorine = mole of Fluorine/ Molarmass of Fluorine

Molarmass of Fluorine = 18.998 x 2 = 37.996 g/mol

Mass of Fluorine = 0.3819mol/37.996g/mol

                              = 14.512g

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.