What volume of concentrated nitric acid (15.0m) is requiredfor
the preperation of 2.00 l of 0.001 m nitric acidsolution.

0.133 mL

Explanation:

Given data

We can find the volume of the concentrated solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.001 M × 2.00 L / 15.0 M

V₁ = 1.33 × 10⁻⁴ L = 0.133 mL

answer; /// i do believe that the correct answer is (a) boiling

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"