The molar heats of fusion and sublimation of molecular
iodineare 15.27 kj/mol and 62.30 kj/mol, respectively. estimate the
molarheat of vaporization of liquid iodine.

47.03 KJ/mol

Explanation:

given:

molar heat of fusion, Hfusion = 15.27 KJ/mol

molar heat of sublimation, Hsublime = 62.30 KJ/mol

molar heat of vaporisation, Hvaporise = ?

Hsublime = Hfusion + Hvaporise

Hvaporise = Hsublime - Hfusion

Hence, the molar heat of vaporization of liquid iodine

= 62.30 - 15.27 = 47.03 KJ/mol

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.