40 ml of 2.0 molar naoh reacts with 8.0 ml of a
monoproticacid. what is the molarity of the acid?

10 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 8.0 mL

M₂ = 2.0 M

V₂ = 40 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

M₁ * 8.0mL = 2.0 M * 40mL

M₁ = 10 M

Hence, the molarity of the acid = 10 M