Consider the solution containing 0.181 m lead ions and
0.174mercury (ii) ions. the ksp for lead sulfide is 3.4 x 10 (to
the-28) and that for mercury (ii) sulfide is 4.0 x 10 (to the-53).
calculate the concentration in m of sulfide ionsrequired to reduce
the concentration of mercury (ii) ions to 1.0 x10 (to the -6)
m.