Balance the equation below and use it to answer thefollowing
questions.

c4h10 + o2 ==> co2
+h2o

how many moles of oxygen are needed to react with 54.7 g
ofbutane?

6.12 mol

Explanation:

Let's consider the following balanced equation.

C₄H₁₀ + 6.5 O₂ → 4 CO₂  + 5 H₂O

We can establish the following relations.

The moles of oxygen needed to react with 54.7 g of butane are:

it is a good conductor

explanation:

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally