Show the calculation of the mass of ca3(po4)2 needed to make 200 ml of a 0.128 m solution.

We need 7.94 grams of Ca3(PO4)2

Explanation:

Step 1: Data given

Volume of Ca3(PO4)2 = 200 mL = 0.2 L

Molarity = 0.128 M

Molar mass of Ca3(PO4)2 = 310.18 g/mol

Step 2: Calculate moles of Ca3(PO4)2

Moles = molarity * volume

Moles Ca3(PO4)2  = 0.128 M * 0.2 L

Moles Ca3(PO4)2  = 0.0256 moles

Step 3: Calculate mass of Ca3(PO4)2

Mass Ca3(PO4)2  = moles Ca3(PO4)2  * molar massCa3(PO4)2

Mass Ca3(PO4)2  = 0.0256 moles * 310.18 g/mol

Mass Ca3(PO4)2  = 7.94 grams

We need 7.94 grams of Ca3(PO4)2

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i  

i think   the answer is c hope i'm right