Chemistry, 10.01.2020 06:31 ptrlvn01

Idon’t know how to do this when the atom is made like this

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Answer from: smarty5187

Atom having maximum mass : B

Atom which has least mass : C

Atom which is neutral : D

Identity of atom D : Lithium

Explanation:

How to look at the Figure :

In the centre : Proton and neutrons are present

$\bigoplus = Proton$

$\bigcirc = Neutron$

In the rings (outside the centre): electrons are present

$\circleddash = electron$

Atomic mass : Total number of proton and neutrons present in the nucleus (centre) of the atom.

To calculate atomic mass count the following symbols :

Atomic mass = Proton + neutron

$\bigoplus$

$\bigcirc$

Figure A

$\bigoplus$ = 4

$\bigcirc$ = 3

Atomic mass = 4 + 3 = 7

Figure B

$\bigoplus$ = 4

$\bigcirc$ = 4

Atomic mass = 4 + 3 = 8

Figure C

$\bigoplus$ = 3

$\bigcirc$ = 3

Atomic mass = 3 + 3 = 6

Figure D

$\bigoplus$ = 3

$\bigcirc$ = 4

Atomic mass = 3 + 4 = 7

Part 1 .So B has maximum atomic mass = 8 amu

Part 2. C has minimum mass = 6 amu

To check whether atoms are neutral or charged :

Count the number of protons and electrons

$\bigoplus = Proton$ = in the centre

$\circleddash = electron$ = outside the centre

If the number of proton and electron are equal, then the atom is neutral

Proton = neutron

If the number of proton and electron are not equal, then the atom is Charged

Figure A. = Charged

$\bigoplus$ = 4

$\circleddash$ = 3

Figure B = Charged

$\bigoplus$ = 4

$\circleddash$ = 3

Figure C = Charged

$\bigoplus$ = 4

$\circleddash$ = 2

Figure D = Neutral (equal number of proton and electron)

$\bigoplus$ = 3

$\circleddash$ = 3

Part C .The atom which is neutral is D

Part DThe identity of Figure D : Lithium

Atomic number : Total number of proton in the nucleus of the atom

$\bigoplus$ = 3 = Proton

So it is Lithium (See the periodic table)

Answer from: Quest

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in $h_{2}s$ , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between $h_{2}s$ molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent $h_{2}s$ molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

Answer from: Quest

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

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