20950 joules of heat are added to a container with 400 g of water. how much does the temperature show work and formula.

Temperature change is 12.5°C

Explanation:

Let's apply the calorimetry formula for this problem

Q = c . m . ΔT

Where Q is heat (energy)

c is, the specific heat ( for water this value is 4.18 J/g°C) -  A constant that is specific to each substance / compound that determines how easy it is to heat or cool that substance

m = mass

ΔT = T° change

20950 J = 4.18 J/°C . 400 g . ΔT

20950 J 7 (4.18 J/°C . 400 g) =  ΔT → 12.5°C

possibly, yes.

explanation:

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