In the example in the lesson, 0.10 mole of sodium chloride or magnesium chloride or aluminum chloride was added to one liter of water. how many moles of each chloride are in one milliliter of the respective solutions?

1x10⁻⁴ moles of Cl⁻ in NaCl solution

2x10⁻⁴ moles of Cl⁻ in MgCl₂ solution

3x10⁻⁴ moles of Cl⁻ in AlCl₃ solution

Explanation:

Let's produce the reactions of each salt

NaCl  → Na⁺ +  Cl⁻

0.1 m                 0.1m

MgCl₂ → Mg²⁺  +  2Cl⁻

0.1m                      0.2m

AlCl₃ → Al³⁺  +  3Cl⁻

0.1 m                 0.3m

0.1, 0.2 and 0.3 are the moles of each chloride in each solution and this moles are added to one liter of solvent.

1 L = 1000mL

Let's prepare the rule of three for each

1000 mL 0.1 m 0.2 m 0.3m

1 mL 1x10⁻⁴ m ___ 2x10⁻⁴ m 3x10⁻⁴ m

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.