Ineed to make this into an ionic equation with state symbols

Pb²⁺(aq) +  2I⁻(aq) ⟶ PbI₂(s)  

Explanation:

There are three steps you must follow. You must write the:

A. Molecular equation

Pb(NO₃)₂(aq) + 2KI(aq) ⟶ PbI₂(s) + 2KNO₃(aq)

B. Ionic equation

You write all the soluble substances as ions.

Pb²⁺(aq)+ 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

C. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

Pb²⁺(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) ⟶ PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

The net ionic equation is

Pb²⁺(aq) +  2I⁻(aq) ⟶ PbI₂(s)  

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.