If 1,079.75 joules of heat are added to 77.75 grams of water, by how many degrees celsius would the water increase? assume water is in the liquid state.

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of  water will increase

Explanation:

Here , q = heat added / removed from the substance

m  = mass of the substance taken

= Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

on transposing ,

am i too late?

explanation: