Aparticular compound in the chemistry laboratory is found to contain 7.2x10^24 atoms of oxygen, 56.0g of nitrogen, and 4.0 mol of hydrogen. what is it’s empirical formula?

The empirical formula for the compound is :

or , NHO3

Explanation:

Empirical formula : It is the simplest ratio of atoms  present in a compound.

Calculate number of moles of H , N and O using formula :

Avogadro number is represented by N0 and contain =

atoms

1.Calculate number of moles of O

Number of Atoms =

Insert value in :

O =  11.95 mole  = 12.0 mole

(11.95 is almost equal to 12 )

2.Calculate number of moles of N

Given mass = 56 .0 g

Molar mass of N = 14 g/mol

N = 4.0 mole

3.Calculate number of moles of H

Already given in moles

H = 4.0 moles

3.Calculate Simple ratio : Divide the moles of each H ,O ,N by the 4.0 mole ( It is the smallest number)

Ratios Are :

O = 3

N = 1

H = 1

So the empirical formula should be :

or

NHO3

the answer

explanation:

the capillary tube was too close to the bottom of the beaker.

the ruler may have moved.

water got into the capillary tube.

the temperature was not allowed to equilibrate in the 2-4 minutes.