Use the following equation to determine how many grams of o2 are required to react with 22.50g of c7h16?

c7h16 + 11o2 --> 7co2 + 8h2o

79.2 grams of oxygen gas are required to react with 22.50 grams of n-heptane.

Explanation:

Mass of n-heptane = 22.50 g

Moles of n-heptane =

According to reaction 1 mole of n-heptane reacts with 11 moles of oxygen gas. then 0.2250 moles of n-heptane will react with:

of oxygen gas

Mass of 2.475 moles of oxygen gas= 2.475 mol × 32 g/mol= 79.2 g

79.2 grams of oxygen gas are required to react with 22.50 grams of n-heptane.

personal, she chose to do it.