Radium decays to form radon. which equation correctly describes this decay?

its d

The equation that correctly describes the decay is :

Ra -----> Rn + He

Explanation:

When the solid radium start decaying in order to form the radon gas, it starts losing two protons with one neutron. The two neutron as well as one proton together forms an alpha particle, hence a type of radiation is formed. Also we know that radon itself is radioactive as it also leads to the decay, after that it loses an alpha particle and also form an element called as polonium. Radium being the most stable form of isotope, radium 226, also holds a half life of 1600 years. It will decay into radon 222 through the alpha decay or can also lead 212 by ejecting a carbon 14 nucleus.

the answer is either b or c

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.