What is the simplest formula of a compound if a sample of the compound contains 0.221 mol x, 0.442 mol y, and 0.884 mol z? xy2z4 xy_2z_4 correct. how many moles of z would be in a sample that contained 0.588 mol x? webassign will check your answer for the correct number of significant figures.

The simplest formula of this compound is XY2Z4

We would have 2.352 moles of Z in a sample that contains 0.588 moles X

Explanation:

Step 1: Data given

A compound contains 3 elements

X = 0.221 mol

Y = 0.442 mol

Z = 0.884 mol

Step 2: Calculate the mol ratio

We divide by the smallest amount of moles

X = 0.221/0.221 = 1

Y = 0.442/0.221 = 2

Z = 0.884/0.221 = 4

The empirical formula is XY2Z4

This means for each 1 X atom we have 2 Y atoms and 4 Z atoms.

If we have 0.588 moles X this means we have 0.588*2 = 1.176 moles of Y

And 0.588 *4 = 1.176*2 = 2.352 moles of Z

The simplest formula of this compound is XY2Z4

We would have 2.352 moles of Z in a sample that contains 0.588 moles X

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

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