Methane and hydrogen sulfide form when hydrogen reacts with carbon disulfide. identify the excess reagent and calculate how much remains after 36 l of h2reacts with 12 l of cs2.

3 Litres.

Explanation:

The balance equation of reaction is written in equation (1) below;

4H2 (g) + CS2(g) > CH4 (g) + 2H2S (g) (1).

(From the balanced equation above) one mole of methane, CH4 and two moles of Hydrogen Sulphide, H2S are being produced when one mole of carbon Sulphide, CS2 reacts with 4 moles of Hydrogen gas.

(Parameters given from the question): we have 36 litres of Hydrogen, H2 gas and 12 litres of carbon Sulphide, CS2 gas.

Therefore, 36 Litres of H2 would react completely with; 36 litres/ 4.

= 9 Litres of Carbon Sulphide.

LIMITING REAGENT: (The reagent that is totally consumed). Hydrogen gas, H2 is the limiting reactant since we have 12 litres of Carbon Sulphide, CS2.

EXCESS REAGENT: Carbon Sulphide.

Amount remaining= 12 Litres of CS2 - 9 litres that was reacted.

= 3 Litres.

- lead + phosphoric acid = hydrogen + lead(ii) phosphate