How much water should be added to 12 ml of 13% alcohol solution to reduce the concentration to 6%?

We have to add 14 mL of water to dilute the alcohol solution from 13% to 6%

Explanation:

Step 1: Data given

Original solution has 12 mL of 13% alcohol

New volume has a concentration of 6%

Step 2:  Determine how much pure alcohol you have in the solution.

0.13 * 12ml = 1.56 ml pure alcohol.

Step 3: Calculate ratio alcohol: total in volume

1.56 ml / 12 ml = .013

Step 4:  add water to the total solution and set the desired percentage

1.56 ml / (12ml + x) = 0.06

1.56 = 0.06 (12 + x)

1.56 = 0.72 + 0.06x

0.84 = 0.06x

x = 14

We have to add 14 mL of water to dilute the alcohol solution from 13% to 6%

is there multiple choice answers?