A58.5 g sample of glass is put into a calorimeter (see sketch at right) that contains 250.0 g of water. the glass sample starts off at 91.2 °c and the temperature of the water starts off at 19.0 °c when the temperature of the water stops changing it's 21.7 the pressure remains constant at 1 atm. calculate the specific heat capacity of glass according to this experiment. be sure your answer is rounded to 2 significant digits

The specific heat of the glass = 0.70 J/g°C

Explanation:

Step 1: Data given

Mass of glass = 58.5 grams

Mass of water = 250.0 grams

Initial temperature of glass = 91.2 °C

Initial temperature of water = 19.0 °C

Final temeprature = 21.7°C  

Pressure = 1 atm

Specific heat capacity of water = 4.184 J/g°C

Step 2: Calculate the specific heat of glass

Heat gained = heat lost

Qwater = -Qglass

Q = m*c*ΔT

m(water) * c(water) * ΔT = -m(glass) * c(glass) * ΔT(glass)

⇒ with mass of water = 250.0 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = T2 - T1 = The change in temperature = 21.7 - 19.0 = 2.7 °C

⇒ with mass of glass = 58.5 grams

⇒ with specific heat of glass = ?

⇒ with ΔT = T2 - T1 = The change in temperature = 21.7 - 91.2 °C = -69,5 °C

250*4.184*2.7 =-58.5*C(glass) * -69.5

2824.2 =4065.75*C(glass)

C(glass) = 0.70 J/g°C

The specific heat of glass = 0.70 J/g°C

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3