How many grams of potassium reacts with 16 grams of oxygen to produce 94 grams of potassium oxide

There will react 78.2 grams of potassium

Explanation:

Step 1: Data given

Potassium = K

Mass of oxygen = 16.00 grams

Mass of potassium oxide produced = 94.00 grams

Molar mass potassium = 39.1 g/mol

Molar mass Oxygen = 32 g/mol

Molar mass potassium oxide = 94.2 g/mol

Step 2: The balanced equation

4K + O2 → 2K2O

Step 3: Calculate moles O2

Moles O2 = mass O2 / molar mass O2

Moles O2 = 16.00 grams / 32 g/mol

Moles O2 = 0.5 moles

Step 4: Calculate moles K2O

Moles K2O = 94.00 grams / 94.2 g/mol

Moles K2O = 1.00 moles

Step 5: Calculate moles of potassium

For 1 moles of O2 we need 4 moles of K to produce 2 moles of K2O

For 0.5 moles O2 we need 4*0.5 moles = 2.0 moles of potassium

Step 6: Calculate mass of potassium

Mass potassium = 2.0 moles * 39.1 g/mol

Mass potassium = 78.2 grams

There will react 78.2 grams of potassium