Aluminum burns in bromine producing aluminum bromide in a certain experiment, 6.0 g aluminum was reacted with an excess of bromine to yield 50.3 g aluminum bromide calculate the theoreteical and percent yields.

Theoretical yield = 59.2 g

Percent yield = 85 %

Explanation:

This is the reaction:

2Al  + 3Br₂  →  2AlBr₃

If the bromine is in excess, we must think that Al is the limiting reagent.

6 g/ 26.98 g/m = 0.222 moles

As ratio is 2:2, the same amount of reactant will produce the same amount of product. Then, 0.222 moles of AlBr₃ are produced.

Molar mass . Mol = Mass

266.68 g/m . 0.222 m = 59.2 g (This is the theoretical yield)

The percent yield will be:

(Produced yield / Theoretical yield) . 100

(50.3 g / 59.2 g) . 100 = 85%

The theoretical yield is 59.2 gram of AlBr3

The % yield is 85.0 %

Explanation:

Step 1: Data given

Mass of aluminium = 6.0 grams

bromine is in excess

Mass of aluminium bromide = 50.3 gram yield

Molar mass of Al = 26.98 g/mol

Molar mass of Br2 = 159.8 g/mol

Molar mass of AlBr3 = 266.69 g/mol

Step 2: The balanced equation

2Al + 3Br2 → 2AlBr3

Step 3: Calculate moles aluminium

moles Al = mass Al / molar mass Al

moles Al = 6.0 grams / 26.98 g/mol

moles Al = 0.222 moles

Step 4: Calculate moles AlBr3

For 2 moles Al we need 3 moles Br2 to produce 2 moles AlBr3

For 0.222 moles Al we'll have 0.222 moles AlBr3

Step 5: Calculate mass AlBr3

Mass AlBr3 = 0.222 moles * 266.69 g/mol

Mass AlBr3 = 59.2 grams

Step 6: Calculate % yield

% yield = (actual yield / theoretical yield )*100%

% yield = (50.3 grams / 59.2 grams)*100%

% yield = 85.0 %

The theoretical yield is 59.2 gram of AlBr3

The % yield is 85.0 %

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).