An analytical chemist determines that an estuarine water sample contains 1.5 g/liter of sulfate ion (so4 2). what is the concentration in terms of: (a) g/l of sulfur? (b) molar concentration of sulfate? (c) normality?

Explanation:

It is known that molar mass of is as follows.

             Molar mass =

                                  = 96 g/mol

It is given that the concentration of is 1.5 g/L.

(a) As 96 g of contains 32 grams of Sulfur in 1 L. And, 1.5 g of contains x grams of sulfur in 1 L.

Therefore, value of x is calculated as follows.

                     x =

                        = 0.5 g/L

Hence, the concentration of sulfur is 0.5 g/L.

(b)  Now, calculate the molar concentration of sulfur as follows.

             Molarity =

                       =

                       = 0.0156 M

Therefore, the molarity of given sample is 0.0156 M.

(c) Calculate the normality as follows.

Equivalent mass of =

                                               = 48 g/mol

       Normality =

                        =

                        = 0.03125 N

Hence, the normality of given sample is 0.03125 N.

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