Chemistry, 16.01.2020 22:31 BreBreDoeCCx

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced according to the balanced chemical equation below:

caco3(s) + 2hc1(aq) 4 cac12(aq) +h20(1) + co2(g)

imagine mixing 2.5 moles of calcium carbonate with 4.8 moles of hydrochloric acid. calculate the number of moles of caco3 and hcl used in the intro activity. determine the limiting reactant and use the ideal gas law to estimate the max volume of co2

Answers: 3

Show answers

Answers

Answer from: Calirose

HCl is limiting reactant.

The maximum volume of the 2.4 moles of carbon dioxide at STP is 53.76 L.

Explanation:

$CaCO_3(s) + 2HC1(aq) \rightarrow4 CaCl_2(aq) +H_2O(l) + CO_2(g)$

Moles of calcium carbonate = 2.5 moles (given)

According to reaction, 1 mole of calcium carbonate react with 2 moles of HCl. then 2.5 moles of calcium carbonate will react with:

$\frac{2}{1}\times 2.5 mol=5.0 mol$ of HCl

Moles of hydrochloric acid = 4.8 moles (given)

According to reaction, 2 mole of HCl react with 1 moles of calcium carbonate. Then 4.8 moles of HCl will react with:

$\frac{1}{2}\times 4.8 mol=2.4 mol$ of calcium carbonate

As we can see that HCl is completely reacting with 2.4 moles of calcium carbonate.Hence HCl is limiting reagent .Also, the moles of carbon dioxide gas will depend upon moles of HCl.

According to reaction, 2 moles of HCl gives 1 mole of carbon dioxide gas. then 4.8 moles of HCl will give:

$\frac{1}{2}\times 4.8 mol=2.4 mol$ of carbon dioxide gas.

To calculate volume of carbon dioxde gas at :

1 mole of ideal gas occupies 22.4 L of volume at STP.

Then 2.4 moles of carbon dioxide will occupy :

$2.4\times 22.4 L=53.76 L$

The maximum volume of the 2.4 moles of carbon dioxide at STP is 53.76 L.

Answer from: Quest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

Electrons are transferred from atoms of to atoms of this transfer makes the sodium atoms and the

Answer from: Quest

what is the question here. i think you messed up.

Another question on Chemistry

Chemistry, 21.06.2019 18:00

Now consider the reaction when 45.0 g naoh have been added. what amount of naoh is this, and what amount of fecl3 can be consumed by it?

Answers: 3

Answer

Chemistry, 22.06.2019 04:20

Which of the following is true for the actual yield of a reaction? it is always calculated as a ratio. it is the yield from the excess reactant. it is the yield from the limiting reactant. it is always less than the theoretical yield.

Answers: 1

Answer

Chemistry, 22.06.2019 08:30

Which of the following would have less momentum than a 52 kg cheetah running at 10 m/s?

Answers: 2

Answer

Chemistry, 22.06.2019 13:30

An animal cell loses the ability to convert energy stored in food to energy that the cell can use. which of the cell's organelles has stopped working? a.the mitochondria b.the nucleus c.the vacuoles d.the endoplasmic reticulum

Answers: 1

Answer

You know the right answer?

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water ar...

Questions