If you take 15.0 ul of a solution with a concentration of 0.0100 m and you dilute it to a total volume of 170.0 ul, what will be the new concentration?

8.82x10⁻³ M will be the new concentration

Explanation:

Let's apply the dilution formula.

C₁ . V₁ = C₂ . V₂

15 μL . 0.01M = 170 μL . C₂

(15 μL . 0.01M) /170 μL = C₂ → 8.82x10⁻³ M

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"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"