In a thermonuclear device, the pressure of 0.050 liters of gas within the bomb casing reaches 4.0x10^6 atm. when the bomb causing is destroyed by the explosion the gas is released into the atom sphere where it reaches a pressure of 1.00 atm. what is the volume of the gas after the explosion?

V₂ = 0.2×10⁶ L

Explanation:

Given data:

Initial volume = 0.050 L

Initial pressure = 4.0×10⁶ atm

Final volume = ?

Final Pressure = 1.00 atm

Solution:

Formula:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = Initial volume

P₂ = Final Pressure

V₂ = Final volume

Now we will put the values in formula.

P₁V₁ = P₂V₂

4.0×10⁶ atm × 0.050 L = 1.0 atm × V₂

V₂ = 0.2×10⁶ atm.L / 1.0 atm

V₂ = 0.2×10⁶ L

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