50.0 grams of acetic acid are required for an experiment. what volume, in milliliters, of a 1.105 g/cm3 acetic acid solution must be measured for the experiment?

45.2 mL must be meausred for the experiment

Explanation:

The density of the acetic acid is 1.105 g/mL, so this data gives the information about how many grams are contained in 1mL of volume.

Notice that 1 mL = 1 cm³

Acetic acid Density = Acetic acid mass / acetic acid volume

1.105 g/mL = 50 g /  acetic acid volume

Acetic acid volume = 50 g / 1.105g/mL ⇒ 42.5 mL

The volume of this acetic acid solution is 45.2 mL

Explanation:

Step 1: Data given

Mass of acetic acid = 50.0 grams

Density = 1.105 grams /cm³ = 1.105 grams /mL

Step 2: Calculate volume acetic acid silution

Density = mass / volume

⇒ Density of acetic acid solution = 1.105 grams / mL

⇒ mass of acetic acid = 50.0 grams

⇒ volume of the acetic acid solution = ?

Volume = mass / density

Volume = 50.0 grams . 1.105 grams / mL

Volume = 45.2 mL

The volume of this acetic acid solution is 45.2 mL

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.