Aperson's blood alcohol (c2h5oh) level can be determined by titrating a sample of blood plasma with a potassium dichromate solution. the balanced equation is 16h+(aq) + 2cr2o72−(aq) + c2h5oh(aq) → 4cr3+(aq) + 2co2(g) + 11h2o(l) if 35.46 ml of 0.05961 m cr2o72− is required to titrate 28.20 g of plasma, what is the mass percent of alcohol in the blood?

0.1727%

Explanation:

Let's consider the following balanced equation.

16 H⁺(aq) + 2 Cr₂O₇²⁻(aq) + C₂H₅OH(aq) → 4 Cr³⁺(aq) + 2 CO₂(g) + 11 H₂O(l)

The moles of Cr₂O₇²⁻ in 35.46 mL of 0.05961 M Cr₂O₇²⁻ are:

35.46 × 10⁻³ L ×  0.05961 mol/L = 2.114 × 10⁻³ mol

The molar ratio of Cr₂O₇²⁻ to C₂H₅OH is 2:1. The moles of C₂H₅OH are 1/2 × 2.114 × 10⁻³ mol = 1.057 × 10⁻³ mol

The molar mass of C₂H₅OH is 46.07 g/mol. The mass corresponding to 1.057 × 10⁻³ moles is:

1.057 × 10⁻³ mol × (46.07 g/mol) = 0.04870 g

The mass percent of alcohol is 28.20 g of plasma is:

(0.04870 g/28.20g) × 100% = 0.1727%

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

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