Amixture of methanol (mw = 32.04 g/mol) and ethanol (mw = 46.07 g/mol) has an average molecular weight of 43.01 g/mol. what is the mol fraction of methanol in this mixture?

The mol fraction of methanol is 0.2181

Explanation:

Step 1: Data given

Molar mass of methanol = 32.04 g/mol

Molar mass of ethanol = 46.07 g/mol

Average molecular weight = 43.01 g/mol

Step 2: Calculate the mol fraction of methanol

Mol fraction = number of moles / total number of moles

We know that mol fraction of methanol + mol fraction of ethanol = 1

Mol fraction methanol = 1 - mol fraction of ethanol

X = 1-Y

Let's consider methanol = X   and ethanol = Y

32.04*X + 46.07*Y = 43.01

32.04*(1-Y) +46.07Y = 43.01

32.04 - 32.04Y + 46.07Y = 43.01

14.03 Y = 10.97

Y = 0.7819

The mol fraction of ethanol is 0.7819

The mol fraction of methanol is 1 - 0.7819 = 0.2181

c8h10 is your answerr